SOLUTION: A dealer has tea worth $1.20 a pound and tea worth $1.90 a pound. How many pounds of each kind must he use to make 70 pounds that can be sold for 1.50 per pound?
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: A dealer has tea worth $1.20 a pound and tea worth $1.90 a pound. How many pounds of each kind must he use to make 70 pounds that can be sold for 1.50 per pound?
Log On
Question 676582: A dealer has tea worth $1.20 a pound and tea worth $1.90 a pound. How many pounds of each kind must he use to make 70 pounds that can be sold for 1.50 per pound? Answer by ewatrrr(24785) (Show Source):
Hi
How many pounds of each kind must he use to make 70 pounds that can be sold for 1.50 per pound?
has tea worth $1.20 a pound and tea worth $1.90 a pound.
Mixing algebraically
1.90x + 1.20(70-x) = 1.50 • 70
.70x = .30• 70
x = 30lb of the $1.90 and 40lb of the $1.20
and
