SOLUTION: a 25% solution of alcohol is to be mixed with a 40% solution to get 50L of a final mixture that is 30% alcohol, how much of each of the original solutions should be used?
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Question 676496: a 25% solution of alcohol is to be mixed with a 40% solution to get 50L of a final mixture that is 30% alcohol, how much of each of the original solutions should be used? Answer by sachi(548) (Show Source):
You can put this solution on YOUR website! say x lof a 25% solution of alcohol is mixed with (50-x)l of a 40% solution to get 50L of a final mixture that is 30% alcohol, (as final volume is 50 l)
so x*25%+(50-x)*40%=50*30%
or 25x+40(50-x)=1500 (multiplying 100 on both sides)
or 25x+2000-50x=1500
or 25x=500
or x=20 l
so 20l of 25% solution of alcohol is mixed with 30l of a 40% solution used
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