SOLUTION: jus need help with finding solution. you may not see the parenthesis around both of the (x+3) in the equation dont know if it matters but my equation is< log(x+3)=log(x+3)+log x>.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: jus need help with finding solution. you may not see the parenthesis around both of the (x+3) in the equation dont know if it matters but my equation is< log(x+3)=log(x+3)+log x>.      Log On


   



Question 676412: jus need help with finding solution. you may not see the parenthesis around both of the (x+3) in the equation dont know if it matters but my equation is< log(x+3)=log(x+3)+log x>. the parenthesis should be there at least thats the question im looking at on my worksheet log%28x%2B3%29=log%28x%2B3%29%2Blog+x its asking me to solve for x
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
the general rules are
+log%28a%29+%2B+log%28b%29++=+log%28+a%2Ab+%29+
and
+log%28a%29+-+log%28b%29++=+log%28+a%2Fb+%29+
+log%281%29+=+0+
+log%28+x%2B3+%29+=+log%28+x%2B3+%29+%2B+log%28x%29+
+log%28+x%2B3+%29+-+log%28+x%2B3+%29+=+log%28x%29+
+log%28+%28x%2B3%29%2F%28x%2B3%29+%29+=+log%28+x+%29+
+log%28+1+%29+=+log%28x%29+
+x+=+1+
-----------
check answer:
+log%28+1%2B3+%29+=+log%28+1%2B3+%29+%2B+log%281%29+
+log%284%29++=+log%284%29+%2B+0+