Question 676329: factor completely: g(x)= -1/4(x^4-x^3-5x^2-x-6) If g(3)=0 and g(4)= -25 1/2
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! factor completely: g(x)= -1/4(x^4-x^3-5x^2-x-6) If g(3)=0 and g(4)= -25 1/2
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Since g(3) = 0, x-3 is a factor of g(x)
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3)....1....-1....-5....-1....-6
......1....2.....1.....2...|..0
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Quotient: x^3+2x^2+x+2
= x^2(x+2)+(x+2)
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= (x+2)(x^2+1)
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g(x) = (-1/4)(x-3)(x+2)(x^2+1)
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Cheers,
stan H.
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