SOLUTION: factor completely 4(x+3)(x+3)-25 okay, i am doing "q-factoring" and all i know is subsitution for the function in parentheses is nesssicary. please help.

Algebra ->  Expressions-with-variables -> SOLUTION: factor completely 4(x+3)(x+3)-25 okay, i am doing "q-factoring" and all i know is subsitution for the function in parentheses is nesssicary. please help.       Log On


   

Question 676263: factor completely
4(x+3)(x+3)-25
okay, i am doing "q-factoring" and all i know is subsitution for the function in parentheses is nesssicary. please help.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




Substitute for





Now it should be clear that you have the difference between two squares. Factor to a pair conjugate binomials and then replace with the original . Finally, simplify both factors.

John

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