SOLUTION: how do you solve log a12 minus 2log a3 1/2 log a25 + 2log a3- log a6
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Question 676131
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how do you solve log a12 minus 2log a3
1/2 log a25 + 2log a3- log a6
Answer by
lwsshak3(11628)
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how do you solve log a12 minus 2log a3
1/2 log a25 + 2log a3- log a6
**
log a(12)-log a(3^2)+log a(√25)+log a(3^2)-log a(6)
log a(12)+log a(√25)+log a(3^2)-(log a(6)-log a(3^2)
log a(12+log a(√25)+log a(3^2)-[(log a(6)+log a(3^2)]
log a[(12*√25*3^2)/(6*3^2)]
log a[(12*√25*3^2)/(6*3^2)]
log a[(12*5)/(6)]
log a(60/6)
log a(10)