SOLUTION: 1) the area of a right triangle is 44m squared. find the lengths of its legs if one of the legs is 3 m longer than the other
2) the hypotneuse of a right triangle is 25m long. t
Algebra ->
Sequences-and-series
-> SOLUTION: 1) the area of a right triangle is 44m squared. find the lengths of its legs if one of the legs is 3 m longer than the other
2) the hypotneuse of a right triangle is 25m long. t
Log On
Question 67603This question is from textbook
: 1) the area of a right triangle is 44m squared. find the lengths of its legs if one of the legs is 3 m longer than the other
2) the hypotneuse of a right triangle is 25m long. the length of one leg is 10m less than twice the other. find the length of each leg.
please show your work
thank you very much!!!!! This question is from textbook
You can put this solution on YOUR website! 1) the area of a right triangle is 44m squared. find the lengths of its legs if one of the legs is 3 m longer than the other
Let one of the legs be "x".
The other leg is "x+3"
Area = (1/2)x(x+3)=44
x(x+3)=88
x^2+3x-88=0
(x+11)(x-8)=0
x= -11 or x=8
--------------------------------
2) the hypotneuse of a right triangle is 25m long. the length of one leg is 10m less than twice the other. find the length of each leg.
Let one of the legs be "x".
The other leg is "2x-10".
Use Pythagoras to get:
x^2+(2x+10)^2 = 25^2
x^2 + 4x^2+40x+100=625
6x^2+40x-525=0
x=[-40+-sqrt(40^2-4*6*-525)/12
x=[-40+-sqrt(14200)]/12
x=6.597 (one of the legs)
2x+10=23.194 (the other leg)
Cheers,
Stan H.
Cheers,
Stan H.
(