SOLUTION: the area of a rectangle is 2x^2-11x+15 square feet. the length of the rectangle is 2x-5 feet. What is the width of the rectangle?

Algebra ->  Rectangles -> SOLUTION: the area of a rectangle is 2x^2-11x+15 square feet. the length of the rectangle is 2x-5 feet. What is the width of the rectangle?      Log On


   

Question 675962: the area of a rectangle is 2x^2-11x+15 square feet. the length of the rectangle is 2x-5 feet. What is the width of the rectangle?
Found 2 solutions by MathLover1, ReadingBoosters:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
the area of a rectangle is A=%282x%5E2-11x%2B15%29ft%5E2
the length of the rectangle is L=%282x-5%29ft
the width W will be

A=L%2AW

W=A%2FL

W=%282x%5E2-11x%2B15%29ft%5E2%2F%282x-5%29ft.....replace -11x with -6x-5x

W=%282x%5E2-6x-5x%2B15%29ft%2F%282x-5%29....group

W=%28%282x%5E2-6x%29-%285x-15%29%29ft%2F%282x-5%29

W=%282x%28x-3%29-5%28x-3%29%29ft%2F%282x-5%29

W=%28%282x-5%29%28x-3%29%29ft%2F%282x-5%29

W=%28cross%28%282x-5%29%29%28x-3%29%29ft%2Fcross%28%282x-5%29%29

highlight%28W=%28x-3%29ft%29



Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
If a = lw, then w = a/l
...
%282x%5E2-11x%2B15%29%2F%282x-5%29
...
(2x-5) goes into 2x%5E2-11x: x
to get
2x%5E2+-+5x
subtracting
2x^2 - 2x^2 - 11x - -5x
yielding
-6x
...
(2x-5) goes into -6x + 15: -3
to get
-6x + 15
subtracting
-6x - -6x + 15 - 15
yielding
0
...
%282x%5E2-11x%2B15%29%2F%282x-5%29+=+%28x-3%29
...
Width is highlight_green%28x-3%29
.....................
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