SOLUTION: 1) find two consecutive odd integers whose product is 143
2) a rectangle is 4 cm longer than it is wide, and its area is 117cm squared. find its dimensions
3)the area of a right
Algebra ->
Sequences-and-series
-> SOLUTION: 1) find two consecutive odd integers whose product is 143
2) a rectangle is 4 cm longer than it is wide, and its area is 117cm squared. find its dimensions
3)the area of a right
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Question 67596This question is from textbook
: 1) find two consecutive odd integers whose product is 143
2) a rectangle is 4 cm longer than it is wide, and its area is 117cm squared. find its dimensions
3)the area of a right triangle is 44m squared. find the lenghts of its legs if one of the legs is 3 m longer than the other
4) the hypotenuse of a right triangle is 25 m long. the length of one leg is 10m less than twice the other. find the length of each leg.
please show your work
thank you This question is from textbook
You can put this solution on YOUR website! x(x+2)=143
x^2+2x-143=0
(x+13)(x-11)=0
x=-13
x=11 solution
x+2=13 solution
proof
11*13=143
143=143
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l=w+4
thus (w+4)w=117
w^2+4w-117=0
(w+13)(w-9)=0
w-9=0
w=8 for the width
l=9+4=13 for the length.
proof
9*13=117
117=117
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