SOLUTION: A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what

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Question 67593This question is from textbook
: A bus leaves a station at 1 P.M., traveling west at an average
rate of 44 mi/h. One hour later a second bus leaves the same station, traveling
east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart? This question is from textbook

Found 2 solutions by checkley71, josmiceli:
Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website!
48(x-1)-44x=274
48x-48-44x=274
4x=274+48
4x=322
x=322/4
x=80.5 hours when they'll be 274 miles apart.

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
The 1st question I asked myself is, how far have they gone when they meet?

At t = 0

At t = 1

At t = 2

notice they're getting closer together
When they meet
44(t + 1) = 48t}}}
48t - 44t = 44}}}

They meet 11 hours after the 2nd bus leaves,
12 hours after the 1st bus leaves

mi

mi so,
If they are getting closer together after starting out 44 mi apart,
they can never be 274 mi apart before they meet
Let's call their meeting point the new starting line and a new t = 0.

hrs
= hours since 1st bus left at 1 PM
= 3 days and 8.5 hours
Add 8.5 to 1 pm to get 9:30 PM 3 days later