SOLUTION: How do you solve x-4/x^2+5 for its vertical asymptotes? Also how would you graph y=.25^x and F(x)=3^(3x-2)?Finally how would you Solve this problem. Use the formula P = le kt, that

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: How do you solve x-4/x^2+5 for its vertical asymptotes? Also how would you graph y=.25^x and F(x)=3^(3x-2)?Finally how would you Solve this problem. Use the formula P = le kt, that      Log On


   

Question 675762: How do you solve x-4/x^2+5 for its vertical asymptotes? Also how would you graph y=.25^x and F(x)=3^(3x-2)?Finally how would you Solve this problem. Use the formula P = le kt, that is, assume exponential growth. A bacterial culture has an initial population of 500. If its population grows to 6000 in 2 hours, what will it be at the end of 4 hours?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do you solve x-4/(x^2+5) for its vertical asymptotes?
It has no vertical asymptotes because the denominator cannot be zero.
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Also how would you graph y = 0.25^x and F(x)=3^(3x-2)?
Plot points to graph each function:
y = 0.25^x
graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C0.25%5Ex%29
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F(x) = 3^(3x-2)
graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C3%5E%283x-2%29%29
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Finally how would you Solve this problem. Use the formula A(t) = Ao*e^(kt), that is, assume exponential growth.
A bacterial culture has an initial population of 500. If its population grows to 6000 in 2 hours, what will it be at the end of 4 hours?
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Solve for "k":
6000 = 500*e^(2k)
e^(2k) = 12
2k = ln(12)
k = 1.2425
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Equation:
A(t) = 500*e^(1.2425t)
A(4) = 500*e^(4*1.2425) = 500*144.03 = 72,013 bacteria
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Cheers,
Stan H.