SOLUTION: in a quadrilateral ABCD A=[3x+5],B=[3x-10],C=[x+25]and D=[2x-15] find the angle of the quadrilateral.

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Question 675664: in a quadrilateral ABCD A=[3x+5],B=[3x-10],C=[x+25]and D=[2x-15] find the angle of the quadrilateral.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
the sum of all angles in a quadrilateral ABCD is 360 degrees
so, A%2BB%2BC%2BD=360
%283x%2B5%29%2B%283x-10%29%2B%28x%2B25%29%2B%282x-15%29=360
3x%2B5%2B3x-10%2Bx%2B25%2B2x-15=360
9x%2B5=360
9x=360-5
9x=355
x=355%2F9
x=39.444

A=3x%2B5
A=3%2A39.44%2B5
A=118.32%2B5
highlight%28A=123.332%29

B=3x-10
B=118.332-10
highlight%28B=108.332%29

C=x%2B25
C=39.444%2B25
highlight%28C=64.444%29


D=2x-15
D=2%2A39.444-15
D=78.888-15
highlight%28D=63.888%29