SOLUTION: i dont know how to solve this problem the orignal equation was y=x/x-2 and i was told to find the inverse of the equation but i dotn remeber how to do it

Algebra ->  Exponents -> SOLUTION: i dont know how to solve this problem the orignal equation was y=x/x-2 and i was told to find the inverse of the equation but i dotn remeber how to do it       Log On


   

Question 675659: i dont know how to solve this problem the orignal equation was y=x/x-2 and i was told to find the inverse of the equation but i dotn remeber how to do it


Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
y=x%2F%28x-2%29.....defined for all x%3C%3E2
integer solutions:
if x=0, than y=0
if x=1, than y=-1
if x=3, than y=3
if x=4, than y=2

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2Cx%2F%28x-2%29%29+

the inverse of the equation:
y=x%2F%28x-2%29.......to solve for "x ":
y%28x-2%29=x
yx-2y=x
yx-x=2y
x%28y-1%29=2y
x=2y%2F%28y-1%29