SOLUTION: solve the equation on the interval [0,2pi) 3cos(x)+6√(3)=cos(x)+5√(3)

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Question 675531: solve the equation on the interval [0,2pi) 3cos(x)+6√(3)=cos(x)+5√(3)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
3cos(x)+6√(3)=cos(x)+5√(3)
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3cos%28x%29%2B6sqrt%283%29=cos%28x%29%2B5sqrt%283%29
2cos%28x%29+=+-sqrt%283%29
cos%28x%29+=+-sqrt%283%29%2F2
x = 5pi/6, 7pi/6