SOLUTION: I am struggling with helping my son on his homework. The problem seems to be missing a quantifying statement to will help delineate the problem. The problem reads as follows:
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Question 675515: I am struggling with helping my son on his homework. The problem seems to be missing a quantifying statement to will help delineate the problem. The problem reads as follows:
" Tickets for a school dance cost $7 in advance and $11 at the door. If 109 students attended the dance and the total spent was $887, how many tickets were bought in advance and how many at the door?"
Thanks in advance
Kevin Found 2 solutions by ReadingBoosters, MathLover1:Answer by ReadingBoosters(3246) (Show Source):
You can put this solution on YOUR website! x = advance
y = door
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x+y = 109
7x+11y=887
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rearrange the first equation as x = 109 - y and substitute into the second equation.
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7(109-y) + 11y = 887
763 - 7y + 11y = 887
4y = 887 - 763
4y = 124 tickets sold at the door
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x = 109 - 31 = tickets in advance
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You can put this solution on YOUR website! stands for advanced tickets stands for door tickets
....eq. 1 ...than .........eq. 2
Now substitute in for in the equation 2
...solve for
now substitute in eq.1 for and find
Now check:
(correct)
(