SOLUTION: A confidence interval estimate for the population mean is given to be (39.86, 47.87). If the standard deviation is 16.219 and the sample size is 63, answer each of the following (

Algebra ->  Probability-and-statistics -> SOLUTION: A confidence interval estimate for the population mean is given to be (39.86, 47.87). If the standard deviation is 16.219 and the sample size is 63, answer each of the following (      Log On


   

Question 675446: A confidence interval estimate for the population mean is given to be (39.86, 47.87). If the standard deviation is 16.219 and the sample size is 63, answer each of the following (show all work):

(A) Determine the maximum error of the estimate, E.

(B) Determine the confidence level used for the given confidence interval.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

A)

E = (b-a)/2

E = (47.87 - 39.86)/2

E = 4.005

So the max error (E) is 4.005 (this is also called the margin of error)


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B)

E = C*s/sqrt(n)

4.005 = C*16.219/sqrt(63)

4.005*sqrt(63) = C*16.219

4.005*sqrt(63)/16.219 = C

C = 4.005*sqrt(63)/16.219

C = 1.959966

So the critical value is 1.959966, which means that the confidence level is 95% (use either a calculator or a table to find this)