SOLUTION: The length of a side of a square is equal to the width of a rectangle. The area of the square is ( 49a^2 + 56ab + 16b^2 ) cm^2 and the area of the rectangle is (56a^2 + 31ab - 3b^2

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: The length of a side of a square is equal to the width of a rectangle. The area of the square is ( 49a^2 + 56ab + 16b^2 ) cm^2 and the area of the rectangle is (56a^2 + 31ab - 3b^2      Log On

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Question 675398: The length of a side of a square is equal to the width of a rectangle. The area of the square is ( 49a^2 + 56ab + 16b^2 ) cm^2 and the area of the rectangle is (56a^2 + 31ab - 3b^2 ) m^2. Find the perimeter of the rectangle??
Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
to find the perimeter of a rectangle all you have to do is
(1)perimeter is 2 times width plus 2 times length
(2) width times length is the area