SOLUTION: two integers differ by 6.The sum of the squares of these integers is 116.Find the two integers

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Question 675324: two integers differ by 6.The sum of the squares of these integers is 116.Find the two integers
Answer by ReadingBoosters(3246) About Me  (Show Source):
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x-y=6
x^2+y^2=116
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substitution
(6+y)^2 + y^2 = 116
36 + 12y + y^2 + y^2 = 116
2y^2 + 12y + 36 - 116 = 0
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2y^2 + 12y - 80 = 0
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divide the entire equation by 2
y^2 +6y - 40 = 0
(y+10)(y-4)
y = 4 an y = -10
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Using the positive integer
x - 4 = 6
x = 6+4 = 10
...
Integers are highlight_green%284%29 and highlight_green%2810%29
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