SOLUTION: Using the common or natural log to solve the exponnential equation symboliccally. 2^(8+4x)=1/16 Can you help me figure out this problem? I have tried to get help from a tutor. W

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Using the common or natural log to solve the exponnential equation symboliccally. 2^(8+4x)=1/16 Can you help me figure out this problem? I have tried to get help from a tutor. W      Log On


   

Question 675254: Using the common or natural log to solve the exponnential equation symboliccally. 2^(8+4x)=1/16
Can you help me figure out this problem? I have tried to get help from a tutor. We worked it out together and we both came up with the same thing that was not an answer choice. I sure would appreciate your help.
Found 2 solutions by ankor@dixie-net.com, MathTherapy:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
2^(8+4x) = 1/16
:
Actually 1%2F16+=+2%5E-4
so we have an equiv equation of:
2%5E%28%288%2B4x%29%29+=+2%5E-4
It the bases are equal, the exponents are equal, so we have:
8 + 4x = -4
4x = -4 - 8
4x = -12
x = -12/4
x = -3
:
:
Check this in your calc: enter 2^(8+4(-3)) results: .0625 which is 1/16

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Using the common or natural log to solve the exponnential equation symboliccally. 2^(8+4x)=1/16
Can you help me figure out this problem? I have tried to get help from a tutor. We worked it out together and we both came up with the same thing that was not an answer choice. I sure would appreciate your help.

Since it's asked to solve using common or natural logs, it'll be done so.

2%5E%288+%2B+4x%29+=+1%2F16

log+%282%2C+1%2F16%29+=+8+%2B+4x

log+%282%2C+4%5E-+2%29+=+8+%2B+4x+

-+2log+%282%2C+4%29+=+8+%2B+4x

– 2 (2) = 8 + 4x

– 4 = 8 + 4x

4x = - 4 – 8

4x = - 12

x+=+%28-+12%29%2F4, or highlight_green%28x+=+-+3%29

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