SOLUTION: (3x^2+2x-5/5x+1)+(2x^2-x+6/5x+1) I have no idea how to do this problem Key ^=exponents /=all over or fraction

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: (3x^2+2x-5/5x+1)+(2x^2-x+6/5x+1) I have no idea how to do this problem Key ^=exponents /=all over or fraction      Log On


   

Question 67508This question is from textbook Algebra 1
: (3x^2+2x-5/5x+1)+(2x^2-x+6/5x+1)
I have no idea how to do this problem
Key ^=exponents /=all over or fraction This question is from textbook Algebra 1

Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
+%28%283x%5E2%2B2x-5%29%2F%285x%2B1%29%29%2B%28%282x%5E2-x%2B6%29%2F%285x%2B1%29%29+
The fractions are already in common denominators.
+%28%283x%5E2%2B2x-5%29%2B%282x%5E2-x%2B6%29%29%2F%285x%2B1%29%29+
Combine like terms
+%285x%5E2%2B1x%2B1%29%2F%285x%2B1%29+
You can not factor the numerator, so unless your instructor wants you to go to imaginary numbers, this is finished.