SOLUTION: indicate the correct conic section for (x^2/9)-(Y^2/16)=1

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Question 674925: indicate the correct conic section for (x^2/9)-(Y^2/16)=1
Answer by lwsshak3(11628) About Me  (Show Source):
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indicate the correct conic section for (x^2/9)-(Y^2/16)=1
standard form of an equation for a hyperbola: %28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1, (h,k)=(x,y) coordinates of center. Given equation is that of a hyperbola with horizontal transverse axis and center at (0,0)