SOLUTION: Solve the system by the method of substitution. (If there is no solution, enter NO SOLUTION.) x-2y=0 3x-y^2=0. i have no clue how to do this or even set it up.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Solve the system by the method of substitution. (If there is no solution, enter NO SOLUTION.) x-2y=0 3x-y^2=0. i have no clue how to do this or even set it up.      Log On


   

Question 674922: Solve the system by the method of substitution. (If there is no solution, enter NO SOLUTION.)
x-2y=0
3x-y^2=0.
i have no clue how to do this or even set it up.
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
x-2y=0
3x-y^2=0
...
solve the first equaiton for x
x = 2y
...
Plug this x into the second equation
3(2y) - y^2 = 0
6y - y^2 = 0
-y^2 + 6y = 0
-y(y-6) = 0
(y-6) = 0
highlight_green%28y+=+6%29
..
Plug y back into the first equation
x-2(6) = 0
x - 12 = 0
highlight_green%28x=12%29
.....................
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-Reading Boosters
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