SOLUTION: A city's skate park is a rectangle 100 feet lony by 50 feet wide. The city wantes to triple the area of the skate park by adding the same distance x to the length and the width. Wr
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Question 674724: A city's skate park is a rectangle 100 feet lony by 50 feet wide. The city wantes to triple the area of the skate park by adding the same distance x to the length and the width. Write and solve an equation to find the value of x. What are the new dimensions of the skate park? Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! 100*50=5000 sq. feet is the area.
(100+x)(50+x)=3*5000
5000+50x+100x+x^2=15000
x^2+150x+5000-15000=0
x^2+150x-10000=0
(x-50)(x+200)=0
x-50=0
x=50 feet must be added to triple the area.
Proof:
(100+50)(50+50)=15000
150*100=15000
15000=15000
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