Question 674689: Two boys, Shawn and Curtis, went for a walk. Shawn began walking 20 seconds earlier than Curtis. Shawn walked at a speed of 5 feet per second. Curtis walked at a speed of 6 feet per second. For how many seconds had Shawn been walking at the moment when the two boys had walked exactly the same distance?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Two boys, Shawn and Curtis, went for a walk.
Shawn began walking 20 seconds earlier than Curtis.
Shawn walked at a speed of 5 feet per second.
Curtis walked at a speed of 6 feet per second.
For how many seconds had Shawn been walking at the moment when the two boys had walked exactly the same distance?
:
let t = walking time of S
then
(t-20) = walking time of C; (started 20 sec after S)
:
Write a distance equation; dist = speed * time
:
5t = 6(t-20)
5t = 6t - 120
120 = 6t - 5t
t = 120 seconds, is S's walking time
:
:
Check this by finding the distance each walked, should be equal
C's walking time = 100 sec
5(120) = 600 ft
6(100) = 600 ft
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