SOLUTION: Multiply (8+2i) (4-3i)

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Question 674632: Multiply
(8+2i) (4-3i)
Answer by ReadingBoosters(3246) About Me  (Show Source):
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FOIL
(8+2i)(4-3i)
...
8(4) + 8(-3i) + 2i(4) - 2i(-3i)
...
32 - 24i + 8i - 6i^2
...
i = sqrt%28-1%29 so i%5E2+=+sqrt%28-1%2A-1%29 = -1
...
32 - 16i -6(-1)
...
32 - 16i + 6
...
highlight_green%2838-16i%29
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