SOLUTION: Suppose X is normally distributed with mean 30 and standard deviation 8, find the value x0 such that P(X ≥ x0) = 0.95.
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Question 674453: Suppose X is normally distributed with mean 30 and standard deviation 8, find the value x0 such that P(X ≥ x0) = 0.95. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Suppose X is normally distributed with mean 30 and standard deviation 8, find the value x0 such that P(X ≥ x0) = 0.95.
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Find the z-value with a left tail of 0.05
invNorm(0.05) = -1.645
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Find the corresponding "x" value using x = z*s+u
xo = -1.645*8 + 30 = 16.84
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Cheers,
Stan H.
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