SOLUTION: The length of a rectangular playing field is 5 ft less than twice its width. If the perimeter of the playing field is 230 ft, find the length and width of the field.
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-> SOLUTION: The length of a rectangular playing field is 5 ft less than twice its width. If the perimeter of the playing field is 230 ft, find the length and width of the field.
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Question 67412: The length of a rectangular playing field is 5 ft less than twice its width. If the perimeter of the playing field is 230 ft, find the length and width of the field. Answer by prabhjyot(165) (Show Source):
You can put this solution on YOUR website! Let the width of the field be x ft.
So length = (2x-5) ft
Perimeter = 2[ length + width]
2[2x-5+x] = 230
2{3x-5} = 230
6x - 10 = 230
6x = 240
x = 40
Thus the width of the field = 40 ft.
Length = 2x-5
= 2*40 - 5
= 80 - 5
= 75
Width = 40 ft and length = 75 ft
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