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Question 674096: If I have a field that is 180 feet long and 75 feet wide what would 80% be? In other words I want if possible someone to figure out what 90% of that size and also 80% of that size? I believe you multiply .80 times the 180 feet and also do the same with 75 feet? I have those figures but they are hard to round out lol lol...thanks
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! If I have a field that is 180 feet long and 75 feet wide what would 80% be?
In other words I want if possible someone to figure out what 90% of that size and also 80% of that size?
:
It's not clear what you want.
Do you want the field to be 80% of the original area but the same shape?
or
Do you want the dimensions of the field to be 80% of the original
:
Let's say you want the new field to be 80% of the old area, but the same shape
Calculate the new dimensions
Find the original area: 180*75 = 13500 sq/ft
Find the new area: .8*13500 = 10800 sq/ft
:
let x = amt subtracted from the original dimensions to obtain 10800 sq/ft
(180-x)*(75-x) = 10800
FOIL
13500 - 180x - 75x + x^2 = 10800
Arrange as a quadratic equation
x^2 - 255x + 13500 - 10800 = 0
x^2 - 255x + 2700 = 0
Using the quadratic formula, a reasonable answer was x = 11 ft
Subtract 11 ft from each dimension: 169 by 64 has an area of 10816 sq/ft, is that close enough?
:
Using the same method for 90% area, I came up with x = 5.4 ft (5 ft 5 in) subtract from each dimension. 174.6 * 69.6 = 12152 sq/ft
Check .9(13500) = 12150
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