SOLUTION: I Computed the following: P(5) using the formula P(x) = –x2 + 110x – 1,000, however i am having trouble on how to graph the function. my result was for the following:P(5) = -(5)2 +

Algebra ->  Linear-equations -> SOLUTION: I Computed the following: P(5) using the formula P(x) = –x2 + 110x – 1,000, however i am having trouble on how to graph the function. my result was for the following:P(5) = -(5)2 +      Log On


   

Question 673845: I Computed the following: P(5) using the formula P(x) = –x2 + 110x – 1,000, however i am having trouble on how to graph the function. my result was for the following:P(5) = -(5)2 + 110(5) – 1,000 to P(5) = -25 + 550 – 1,000 to P(5) = -475 (or calculated in thousands 475,000)Now im not sure how to graph it. can you help me?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

P(x) = –x^2 + 110x – 1,000  || yes,  P(5)= -475

P(x) = -(x-55)^2 + 55^2 - 1000

P(x) = -(x-55)^2 + 2025  ||Parabola opening downward V(55,2025)

 0 = -(x-55)^2 + 2025

(x-55)^2 =  2025 

    x =  55 ± 45,   x-intercepts are 10 and 100

sketching:  important to get in your Vertex and x-intercepts