SOLUTION: A circle has the equation 2(x-2)^2+2y^2=2 find center h,k and radius r graph the circle find intercepts if any

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: A circle has the equation 2(x-2)^2+2y^2=2 find center h,k and radius r graph the circle find intercepts if any      Log On


   



Question 673785: A circle has the equation 2(x-2)^2+2y^2=2 find center h,k and radius r graph the circle find intercepts if any
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
2(x-2)^2+2y^2=2
%28x-2%29%5E2+%2B+y%5E2=+1+=+1%5E2 C(2,0), r = 1
y = 0 ⇒ x^2 - 4x +3 =(x-3)(x-1) = 0 x =1 and x = 3 the x-intercepts