SOLUTION: What are the coordinates of the center of the hyperbola graphed by the equation below? (x+14)^2/7^2-(y+12)^2/6^2=1

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What are the coordinates of the center of the hyperbola graphed by the equation below? (x+14)^2/7^2-(y+12)^2/6^2=1      Log On


   

Question 673751: What are the coordinates of the center of the hyperbola graphed by the equation below? (x+14)^2/7^2-(y+12)^2/6^2=1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

%28x%2B14%29%5E2%2F7%5E2-%28y%2B12%29%5E2%2F6%5E2=1   C(-14,-12)

Standard Form of an Equation of an Hyperbola opening right and  left is:

  %28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1 with C(h,k) 

and vertices 'a' units right and left of center,