SOLUTION: how do i find the slope and y intercept of an equationlike 5x+4y=23

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Question 673722: how do i find the slope and y intercept of an equationlike 5x+4y=23
Found 4 solutions by lynnlo, ReadingBoosters, Edwin McCravy, ewatrrr:
Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
slope===============-5/4
y intercept===23/4

Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
Arrange in slope intercept form: y = mx + b
...
4y = -5x + 23
...
Divide both sides by 4
y = %28-5%2F4%29x+%2B+23%2F4
...
Slope = -5%2F4
y intercept = 23%2F4
.....................
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Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
1. Solve the equation for y to get it in the 
form  y = mx+b.

5x + 4y = 23 

Add -5x to both sides:

     4y = -5x + 23

Divide each number by 4

    4%2F4y = %28-5%29%2F4x + 23%2F4

             y = -5%2F4x + 23%2F4

2. Compare that to

             y = mx + b

Then m = -5%2F4 and b = 23%2F4

That means the slope is -5%2F4 and the y-intercept is 
the point (0,23%2F4), where the graph (which is a line)
crosses the y-axis.

Edwin

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Use the standard slope-intercept form for an equation of a line y = mx + b

  where m is the slope and b the y-intercept.

5x+4y=23   0r  y = (-5/4)x + 23/4   || m = -5/4  and 23/4 the y-intercept