SOLUTION: I'm having difficulties with this one. Can someone please walk me through the steps in order to solve? Thank you! Essay: Show all work. Find the quotient: (6x^3-7x^2-6x-8)/(2x+

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I'm having difficulties with this one. Can someone please walk me through the steps in order to solve? Thank you! Essay: Show all work. Find the quotient: (6x^3-7x^2-6x-8)/(2x+      Log On


   

Question 673640: I'm having difficulties with this one. Can someone please walk me through the steps in order to solve? Thank you!
Essay: Show all work. Find the quotient:
(6x^3-7x^2-6x-8)/(2x+3)
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
%286x%5E3+-+7x%5E2+-+6x+-+8%29%2F%282x%2B3%29
...
2x+3 goes into 6x%5E3+-+7x%5E2: 3x%5E2
to get
6x%5E3+%2B+9x%5E2
subtracting
6x%5E3+-+7x%5E2+-+6x%5E3+-+9x%5E2+=+-16x%5E2
...
2x+3 goes into -16x%5E2+-+6x: -8x
to get
-16x%5E2-24x
subtracting
-16x%5E2+-+6x+-+-16x%5E2+-+-24x+=+18x
...
2x+3 goes into 18x - 8: 9
to get
18x+%2B+27
subtracting
18x+-+8+-+18x+-+27+=+-35
...

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