Question 673609: There are 9 different teams, and each team can either win, lose or tie. How many different possibilities is there if i want to make a list with all the teams and choose their result and one of them will have all the correct results?
Answer by chandrumail(4)   (Show Source):
You can put this solution on YOUR website! Each team has 3 possibilities WIN, LOSE, TIE
Possible outcomes for the 1st team = 3 (WIN, LOSE, TIE)
Possible outcomes for the 2nd team = 3 (WIN, LOSE, TIE)
Possible outcomes for the 3rd team = 3 (WIN, LOSE, TIE)
Possible outcomes for the 4th team = 3 (WIN, LOSE, TIE)
Possible outcomes for the 5th team = 3 (WIN, LOSE, TIE)
Possible outcomes for the 6th team = 3 (WIN, LOSE, TIE)
Possible outcomes for the 7th team = 3 (WIN, LOSE, TIE)
Possible outcomes for the 8th team = 3 (WIN, LOSE, TIE)
Possible outcomes for the 9th team = 3 (WIN, LOSE, TIE)
The point to note here is these outcomes are independent. i.e. the outcome of one team does not affect the other team's outcome.
SO, total no of possible outcomes = 3*3*3*3*3*3*3*3*3 = 3 to the power 9 = 19683
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