SOLUTION: The stopping distance (D) of a vehicle varies directly as the square of its velocity (V). If a vehicle traveling 40 mph requires 100 feet to come to a stop, find the stopping dist
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Question 673595: The stopping distance (D) of a vehicle varies directly as the square of its velocity (V). If a vehicle traveling 40 mph requires 100 feet to come to a stop, find the stopping distance of a vehicle traveling 60 mph.
I started with y=kx for "varies directly" and did not know where to go from there. Also, I am not sure that I am using the correct method in considering this problem. The "square of its velocity" is throwing me off. Found 2 solutions by sachi, MathTherapy:Answer by sachi(548) (Show Source):
You can put this solution on YOUR website! stopping distance (D) of a vehicle varies directly as the square of its velocity (V)
so D/V2=const
or 100/(40)2=D/(60)2
or D=100*(60/40)2=150 feet
ans
You can put this solution on YOUR website!
The stopping distance (D) of a vehicle varies directly as the square of its velocity (V). If a vehicle traveling 40 mph requires 100 feet to come to a stop, find the stopping distance of a vehicle traveling 60 mph.
Since the stopping distance varies directly as the square of its velocity (V), then:
, with k being the constant of variation
100 = 1,600k
k = , or
D, or stopping distance = ft
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