SOLUTION: Write the standard equation for each Hyperbola. vertices ( 0, -12) ( 0, 12) and co-vertices (-11, 0) (11, 0)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Write the standard equation for each Hyperbola. vertices ( 0, -12) ( 0, 12) and co-vertices (-11, 0) (11, 0)       Log On


   



Question 673196: Write the standard equation for each Hyperbola.
vertices ( 0, -12) ( 0, 12) and co-vertices (-11, 0) (11, 0)

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Write the standard equation for each Hyperbola.
vertices ( 0, -12) ( 0, 12) and co-vertices (-11, 0) (11, 0)
***
This is a hyperbola with vertical transverse axis.
Its standard form of equation:%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1, (h,k)=(x,y) coordinates of center.
For given hyperbola:
center: (0,0) (midpoints of horizontal conjugate axis and vertical transverse axis)
length of vertical transverse axis=24 (-12 to 12)=2a
a=12
a^2=144
length of horizontal conjugate axis=22 (-11 to 11)=2b
b=11
b^2=121
Equation of given hyperbola:
y%5E2%2F144-x%5E2%2F121=1