Sorry, that's wrong. Do it this way:
 First equation:   8x - 6y =  4
Second equation:   2x -  y = -2
Solve the second equation for y, that's because y in the
second equation has a coefficient of -1 and that makes 
it solvable without fractions:
Second equation:   2x -  y = -2
                        -y = -2 - 2x
Consider the coefficient of y to be -1
                       -1y = -2 - 2x
Then divide through by -1
                        =
 =  -
 -  y = 2 + 2x
Since y and 2 + 2x are equal you can sustitute (2 + 2x) in place of y in
the first equation:
 First equation:   8x - 6y = 4
                   8x - 6(2 + 2x) = 4
Solve that for x:  
                    8x - 12 - 12x = 4 
                         -4x - 12 = 4
                              -4x = 16
                                x =
                         y = 2 + 2x
Since y and 2 + 2x are equal you can sustitute (2 + 2x) in place of y in
the first equation:
 First equation:   8x - 6y = 4
                   8x - 6(2 + 2x) = 4
Solve that for x:  
                    8x - 12 - 12x = 4 
                         -4x - 12 = 4
                              -4x = 16
                                x =  x = -4
Go back to where you solved for y
                                y = 2 + 2x
and since x and -4 are equal you can substitute (-4) for x
and find y:
                               y = 2 + 2x
                               y = 2 + 2(-4)
                               y = 2 - 8
                               y = -6
So the solution is x = -4, y = -6, often written as (x,y) = (-4,-6)
Edwin
                                x = -4
Go back to where you solved for y
                                y = 2 + 2x
and since x and -4 are equal you can substitute (-4) for x
and find y:
                               y = 2 + 2x
                               y = 2 + 2(-4)
                               y = 2 - 8
                               y = -6
So the solution is x = -4, y = -6, often written as (x,y) = (-4,-6)
Edwin