SOLUTION: 3{ [4 (x-1) +5] - [ 2 ( 2x-1) +5]} i know "pemdas", but i cant figure this out. I dont get when to apply the distributive law, and how this cancles out. I guess the order us me

Algebra ->  Test -> SOLUTION: 3{ [4 (x-1) +5] - [ 2 ( 2x-1) +5]} i know "pemdas", but i cant figure this out. I dont get when to apply the distributive law, and how this cancles out. I guess the order us me      Log On


   



Question 672714: 3{ [4 (x-1) +5] - [ 2 ( 2x-1) +5]}
i know "pemdas", but i cant figure this out. I dont get when to apply the distributive law, and how this cancles out. I guess the order us messing me up.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Always work from the inside out
+3%2A%28+%28+4%2A%28x-1%29+%2B+5+%29+-+%28+2%2A%28+2x-1+%29+%2B+5+%29%29+
One check that you can do is just count the
number of ( 's and the number of ) 's -they
should be the same. In this problem, they
both are 5.
------------
first step:
+3%2A%28+%28+4x+-+4+%2B+5+%29+-+%28+4x+-+2+%2B+5+%29%29+
Now simplify:
+3%2A%28%28+4x+%2B+1+%29+-+%28+4x+%2B+3+%29%29+
The +4x+%2B+1+ doesn't really need to be in
parentheses at this point, also, do the
subtraction using distributive law.
+3%2A%28+4x+%2B+1+-+4x+-+3+%29+
+3%2A%28+-2+%29+
+-6+
Note that it doesn't matter what +x+ is,
the result is still +-6+