SOLUTION: How would I test for intercepts. I have to show the steps to test the intercepts. If anyone could help me, that would be fantastic!!!! X^2+y^2+12x+10y+61=16 X^2+12x+36+y^2+

Algebra ->  Graphs -> SOLUTION: How would I test for intercepts. I have to show the steps to test the intercepts. If anyone could help me, that would be fantastic!!!! X^2+y^2+12x+10y+61=16 X^2+12x+36+y^2+      Log On


   



Question 672608: How would I test for intercepts. I have to show the steps to test the intercepts. If anyone could help me, that would be fantastic!!!!
X^2+y^2+12x+10y+61=16
X^2+12x+36+y^2+10y+25=-45+36+25
(x+6)^2+(y+5)^2=16
C (-6, -5) and r=4

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How would I test for intercepts. I have to show the steps to test the intercepts. If anyone could help me, that would be fantastic!!!!
X^2+y^2+12x+10y+61=16
X^2+12x+36+y^2+10y+25=-45+36+25
(x+6)^2+(y+5)^2=16
C (-6, -5) and r=4
**
x-intercepts, set y=0
(x+6)^2+(y+5)^2=16
(x+6)^2+(0+5)^2=16
(x+6)^2+25=16
(x+6)^2=-9
(x+6)=±√-9=±3i
no real roots
x-intercepts: none
..
y-intercepts, set x=0
(0+6)^2+(y+5)^2=16
36+(y+5)^2=16
(y+5)^2=-20
(y+5)^2=-20
(y+5)=±√-20=±√20 i
no real roots
y-intercepts: none