Question 672263: Formula Rate*Time=Distance.
A previous distance a Frisbee traveled was 30 feet at a rate of 3 feet per 3 seconds, the current rate a second Frisbee is traveling is 3 feet per 3 seconds. Can I assume that this second Frisbee will travel 30 feet based on the previous rate of 3 feet per time of 3 seconds?
Is this how to use the rate*time=distance formula to discover distance?
Can you please provide quick example of correct usage of the formula to predict the distance a Frisbee will travel?
Thank you.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A previous distance a Frisbee traveled was 30 feet at a rate of 3 feet per 3 seconds, the current rate a second Frisbee is traveling is 3 feet per 3 seconds. Can I assume that this second Frisbee will travel 30 feet based on the previous rate of 3 feet per time of 3 seconds?
Is this how to use the rate*time=distance formula to discover distance?
Can you please provide quick example of correct usage of the formula to predict the distance a Frisbee will travel?
------------------
Dist = rate*time
30 ft at a rate of 3 feet per 3 seconds
30 ft = (3 ft/3sec)*time
30 ft = (1 ft/sec)*time
time = 30 seconds
--------------------------
"Can I assume that this second Frisbee will travel 30 feet based on the previous rate of 3 feet per time of 3 seconds?"
Answer: No
It's traveling 30 feet depends on the time it maintains 3 ft/3 sec or 1 ft/sec.
====================================
In other words, the distance does not just depend on the rate, it also
depends on the time.
========================
That is what d = r*t means
=========================
Cheers,
Stan H.
|
|
|
