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Question 672210: Consider the following.
Point: (6,1) Line: 6x − 2y =1
(a) Write the slope-intercept form of the equation of the line through the given point and parallel to the given line.
y =
(b) Write the slope-intercept form of the equation of the line through the given point and perpendicular to the given line.
y =
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Consider the following.
Point: (6,1) Line: 6x − 2y =1
(a) Write the slope-intercept form of the equation of the line through the given point and parallel to the given line.
y =
(b) Write the slope-intercept form of the equation of the line through the given point and perpendicular to the given line.
y =
**
Standard form of equation for a line: y=mx+b, m=slope, b=y-intercept
equation of given line:
6x-2y=1
2y=-6x+1
y=-3x+1/2
slope,m=-6
..
(a) slope of line parallel to given line=-6 (same as that of given line)
Equation: y=-6x+b
solve for b using given point (6,1)
1=-6*6+b
1=-36+b
b=37
Equation of parallel line: y=-6x+37
..
(b) slope of line perpendicular to given line=1/6 (negative reciprocal of slope of given line)
Equation: y=x/6+b
solve for b using given point (6,1)
1=6/6+b
1=1+b
b=0
Equation of perpendicular line: y=x/6
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