SOLUTION: Solve for x: (A.) Log(base 5)7 + log(base 5)8 = log(base 5)(2x-4) (B.) Log(base 3) (x+1) - log(base 3) x = log(base 3) 15 (C.) (3/4)log(base 10) 10,000 = x

Algebra ->  Formulas -> SOLUTION: Solve for x: (A.) Log(base 5)7 + log(base 5)8 = log(base 5)(2x-4) (B.) Log(base 3) (x+1) - log(base 3) x = log(base 3) 15 (C.) (3/4)log(base 10) 10,000 = x      Log On


   

Question 67219This question is from textbook Advanced mathematics
: Solve for x:
(A.) Log(base 5)7 + log(base 5)8 = log(base 5)(2x-4)
(B.) Log(base 3) (x+1) - log(base 3) x = log(base 3) 15
(C.) (3/4)log(base 10) 10,000 = x This question is from textbook Advanced mathematics

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
(A.) log(base 5)7 + log(base 5)8 = log(base 5)(2x-4)
log%285%2C7%29+%2B+log%285%2C8%29+=+log%285%2C2x+-+4%29
log%285%2C7%2A8%29+=+log%285%2C%282x+-+4%29%29
56+=+2x+-+4
60+=+2x
30+=+x
(B.) log(base 3) (x+1) - log(base 3) x = log(base 3) 15
log%283%2Cx+%2B+1%29+-+log%283%2Cx%29+=+log%283%2C15%29
log%283%2C%28x+%2B+1%29%2Fx%29+=+log%283%2C15%29
%28x+%2B+1%29%2Fx+=+15
x+%2B+1+=+15x
1+=+14x
1%2F14+=+x
(C.) (3/4)log(base 10) 10,000 = x
%283%2F4%29log%2810%2C10000%29+=+x
%283%2F4%29%284%29+=+x
3+=+x