SOLUTION: write the standard form of the equation of the line passing through the points (-3,2) and perpendicular to the line 3x-5y=-15

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Question 672039: write the standard form of the equation of the line passing through the points (-3,2) and perpendicular to the line 3x-5y=-15
Answer by VirtualMathTutor(26) About Me  (Show Source):
You can put this solution on YOUR website!
First find the slope of the line given by solving for y:
3x - 5y = -15
-5y = -15 - 3x
divide both sides by -5
y = 3 + 3%2F5x
Slope m is the coefficient of x which is 3%2F5
Since our line is perpendicular to the given line, the slope will be the negative reciprocal of the given slope = -5%2F3
To find the equation use the formula y - y1 = m(x - x1)
x1 = -3
y1 = 2
y - 2 = -5%2F3(x - (-3))
y - 2 = -5%2F3(x + 3)
y - 2 = -5%2F3x - 5
add 2 to both sides
y = -5%2F3x - 3
In standar form:
y + 5%2F3x = -3