SOLUTION: eight divided by the difference of a numer and 3 minus 7 divided by a number plus 3, equals 2 times the reciprocal of the difference of the number sqaured and 9. What is the number

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Question 671814: eight divided by the difference of a numer and 3 minus 7 divided by a number plus 3, equals 2 times the reciprocal of the difference of the number sqaured and 9. What is the number? is the problem and I'm having a hard time figuring out how to write out the last half of it.
Answer by MathTherapy(10557) About Me  (Show Source):
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eight divided by the difference of a numer and 3 minus 7 divided by a number plus 3, equals 2 times the reciprocal of the difference of the number sqaured and 9. What is the number? is the problem and I'm having a hard time figuring out how to write out the last half of it.

Let the number be N
Then: 8%2F%28N+-+3%29+-+7%2F%28N+%2B+3%29+=+2%281%2F%28N%5E2+-+9%29%29

8%2F%28N+-+3%29+-+7%2F%28N+%2B+3%29+=+2%2F%28N%5E2+-+9%29
8(N + 3) – 7(N – 3) = 2 ------ Multiplying by LCD, (N – 3)(N + 3), or N%5E2+-+9
8N + 24 – 7N + 21 = 2
8N – 7N + 45 = 2
N = 2 - 45

N, or number = highlight_green%28-+43%29

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