SOLUTION: how to solve logx 49/64= -2
solve for x:
logx 2=1/3
simplify log2 2^2=log5 5^2-log4 4^2
find antilog base of 9 power of 3
write as a single logarithim: 3 log(y^2-9)-4
Question 671398: how to solve logx 49/64= -2
solve for x:
logx 2=1/3
simplify log2 2^2=log5 5^2-log4 4^2
find antilog base of 9 power of 3
write as a single logarithim: 3 log(y^2-9)-4 log x-4 log(y+3)+log(3x+xy) Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! how to solve logx 49/64= -2
x^-2=49/64
1/x^2=49/64
take sqrt of both sides
1/x=7/8
x=8/7
..
solve for x:
logx 2=1/3
x^1/3=2
cube both sides
x=2^3
x=8
..
simplify log2 2^2=log5 5^2-log4 4^2
log of base raised to a power=power
2=2-2
2≠0 (no solution)
..
find antilog base of 9 power of 3
9^3=729
base(9) raised to log of number(3)=number (729)
..
write as a single logarithim:
3 log(y^2-9)-4 log x-4 log(y+3)+log(3x+xy)
log[(y^2-9)^3*(3x+xy)/(x^4)*(y+3)^4]
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