SOLUTION: Complete the square and write the equation of the circle in standard form x^2+Y^2-x+10y+25=0 The equation in standard form is The center is The radius is

Algebra ->  Rational-functions -> SOLUTION: Complete the square and write the equation of the circle in standard form x^2+Y^2-x+10y+25=0 The equation in standard form is The center is The radius is      Log On


   

Question 671346: Complete the square and write the equation of the circle in standard form
x^2+Y^2-x+10y+25=0
The equation in standard form is
The center is
The radius is
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square and write the equation of the circle in standard form
x^2+Y^2-x+10y+25=0
------
x^2 -x + (1/4) + y^2+10y+25 = 1/4
(x-(1/2))^2 + (y+5)^2 = 1/4
------------------------------------
The equation in standard form is
The center is ((1/2) , -5)
The radius is r = 1/2
=============================
Cheers,
Stan H.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

x^2+Y^2-x+10y+25=0

x^2+Y^2-x+10y= -25

 (x-1/2)^2 + (y+5)^2 = -25 + 1/4 + 25

+%28x-1%2F2%29%5E2+%2B+%28y%2B5%29%5E2+=+1%2F4+=+%281%2F2%29%5E2  C(.5,-5), r = 1/2