SOLUTION: I would just like for someone to check if my answers are right..
It says, " find the equation for f^-1(x)"
f(x)= -3x i got f^-1(x)= -x/3
f(x)= x-7 i got f^-1(x)= x +7
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Exponential-and-logarithmic-functions
-> SOLUTION: I would just like for someone to check if my answers are right..
It says, " find the equation for f^-1(x)"
f(x)= -3x i got f^-1(x)= -x/3
f(x)= x-7 i got f^-1(x)= x +7
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Question 671265: I would just like for someone to check if my answers are right..
It says, " find the equation for f^-1(x)"
f(x)= -3x i got f^-1(x)= -x/3
f(x)= x-7 i got f^-1(x)= x +7
f(x)= (-2/5)x + 10 i got f^-1(x)= -5/2x+ 25
f(x)= square root of 4x-3 i got f^-1(x)= square root of x/2 + 1.73
f(x) = x^2 + 1 i got f^-1(x)= square root of x -1
if you could help that would be great, thanks! Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! I would just like for someone to check if my answers are right..
It says, " find the equation for f^-1(x)"
f(x)= -3x i got f^-1(x)= -x/3
That's what I get.
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f(x)= x-7 i got f^-1(x)= x +7
Looks right to me.
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f(x)= (-2/5)x + 10 i got f^-1(x)= -5/2x+ 25
= (-5/2)x + 25, not 5/(2x) + 25 Add parentheses.
Or -5x/2 + 25
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f(x)= square root of 4x-3 i got f^-1(x)= square root of x/2 + 1.73
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Be careful of the rules of functions and inverses on this one.
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f(x) = x^2 + 1 i got f^-1(x)= square root of x -1
Same. sqrt(x-1) Make it clear what's under the radical.
