SOLUTION: Question Find the exact solution to the equation in the interval [2π, 3π]. cos (t) = sqrt (3) over 2

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Question 671109: Question Find the exact solution to the equation in the interval [2π, 3π].
cos (t) = sqrt (3) over 2
Answer by lwsshak3(11628) About Me  (Show Source):
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Question Find the exact solution to the equation in the interval [2π, 3π].
cos (t) = sqrt (3) over 2
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given interval [2π, 3π] covers quadrants I and II. cos>0 in I and <0 in II
so cos√3/2=π/6