SOLUTION: An experienced painter made $600 for working on a certain job. His apprentice, who makes $3 per hour less, also made $600. However, the apprentice worked 10 hours more then the p

Algebra ->  Rate-of-work-word-problems -> SOLUTION: An experienced painter made $600 for working on a certain job. His apprentice, who makes $3 per hour less, also made $600. However, the apprentice worked 10 hours more then the p      Log On


   



Question 671: An experienced painter made $600 for working on a certain job. His apprentice, who makes $3 per hour less, also made $600. However, the apprentice worked 10 hours more then the painter. How much does the painter make per hour?
Answer by arden42(16) About Me  (Show Source):
You can put this solution on YOUR website!
Lets call the painter's hourly rate p, the apprentice's hourly rate a, the painter's hours i and the apprentice's hours h.
This is what we know so far:
a+=+p-3
h=i%2B10
ha+=+600
ip+=+600
Substituting the first and second equations into the 3rd gives:
%28i%2B10%29%28p-3%29+=+600
Since we know ip also equals 600 (according to the 4th equation above), we can say:
%28i%2B10%29%28p-3%29+=+ip
Expand the brackets:
ip+%2B10p+-3i+-30+=+ip
Since we want to find p, we need to express i in terms of p. To do this, we make i the subject:
3i+=+10p+-30
i+=+10p%2F3+-+10
Now, if we substitute this value for i into the 4th of our original equations:
p%2810p%2F3+-+10%29+=+600
Expand the brackets:
%2810p%5E2%29%2F3+-+10p+=+600
Remove fractions and get everything on one side:
10p%5E2+-+30p+-+1800+=+0
Divide everything by 10:
p%5E2+-+3p+-+180+=+0
Now we have a quadratic we can factorise:
%28p-15%29%28p%2B12%29+=+0
So p equals either 15 or -12. Since the painter can't be charging a negative rate, he must earn $15 an hour.