SOLUTION: A man is three times as old as his sister. Two years ago, the man was five times as old as his sister was 4 years ago. Find thier present ages.

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Question 670985: A man is three times as old as his sister. Two years ago, the man was five times as old as his sister was 4 years ago. Find thier present ages.
Answer by partha_ban(41) About Me  (Show Source):
You can put this solution on YOUR website!
Let sister's age = s
Man's age = 3s
*
Man's age 2 years ago = 3s - 2
Sister's age 4 years ago = s - 4
*
By condition, 3s - 2 = 5 * (s - 4)
3s - 2 = 5s - 20
3s - 5s = -20 + 2
-2s = -18
s+=+%28-18%29%2F%28-2%29+=+9
*
Present age of sister = 9 years
and man = 3*9 = 27 years